equilateral triangle height
2010

Find the area of an equilateral triangle in which the height is 3 square root 3.?
Find the area of an equilateral triangle in which the height is 3 square root 3.
If the altitude (height) is 3 sqrt (3), then the length of one side is 6 units. This can be found using the Pythagorean theorem in the triangle formed by half of the equilateral triangle. Let x = the length of the shorter leg. Then 2x is the length of the hypotenuse (the side of the equilateral triangle). The third side is the altitude – (3). 3sqrt x ^ 2 + [3sqrt (3)] ^ 2 = 4x ^ 2 x ^ 2 + 27 = 3x 4x ^ 2 ^ 2 = 27 x ^ 2 = 9 x = 3 … (OR x = -3, but this makes no sense as long!) So, 2x = 6. So the length of one side of the equilateral triangle is 6 units. So the area is A = (1 / 2) * 6 * 3sqrt (3) A 9 = sqrt (3) units ^ 2 I hope this helps!
Challenge-All Triangles Base=8 and Height=3
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