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Find the area of the isosceles trapezoid. (Use the Pythagorean theorem.)?

atrapezoid is drawn: the samll base is 7 cm, height is 12 cm, congruence legs 13 cm each. My response was 123.5'm right? And my second question is about a comet is drawn: the side are two small congruent 5 cm in the diagonal connecting the vertex of the kit is cut by the smaller diagonal connecting the two points of the diagonal nonvertex longer be divided into two parts that are 10 cm and 3 cm. my answer is 80 please some help

If I have the right of the description, you must use Pyth. to find the tract that lack of congruent triangles at each end of the trap. formed by a fallen high. With one leg of 12 and a hypotenuse of 13, the leg must be missing 5. (This is one of the Pythagorean triples you can memorize instead of using the theorem). So the longer base should be 5 on each end, plus the 7 is identical to the lower base. This gives us a base of 17 (5 + 7 + 5) and the basis of other than 7 and a height of 12. Plug in the area formula A = 1 / 2 (b1 + b2) h A = 1 / 2 (17 + 7) (12) A = 1 / 2 (24) (12) A = 144 square centimeters. I'm sure his answer came, but you're not too far. 2nd question, I'm assuming that you are searching the area again. On the side of the comet with 2 congruent triangles with the right hypotenuse 5 and a length of 3, those legs that are missing pieces of the short diagonal is 4 each. You now have enough information to find the area. You have two congruent triangles, formed by the longest diagonal of length 13. Each of these triangles must have a height of 4. Each triangle has an area of 1 / 2 (13) (4) = 26, which means that the total area of the kite is 52 cm square. Indeed, there is a shortcut for a kite area A = 1 / 2 (1 diagonal) (diagonal 2). Good luck with the rest of geometry!

Isosceles Trapezoid Area

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