max height projectile motion

May 29
2009

Height Now System

How is the X and components and speed and distance of motion of a projectile at a given time?

the projectile was initially launched with an initial velocity of 100 m / s at an angle of 30 degrees. I found the initial x and y components of velocity as follows: Vx = 100 m / s (cos30) = 86.6m / s Vy = 100m / s (sin 30) = 50.0 m / s, I also found the maximum height of 127.42m missile that: y = (Vyo ^ 2 – V) / 2 g = ( 50m / s) ^ 2 / 2 (9.81m / s ^ 2) = 127.42 m now I am supposed to find the X and y components of the velocity after the projectile has been in motion for 7s, and displacement from horizon to 7 seconds. Can anyone shed some light as how to do this?

Since there is no force in the x direction component x of the velocity does not change from its initial velocity 86.6m / s. Since the x component does not change the distance traveled is given by the speed * time to be 86.6m / s * 7s For the y component of velocity to be finding time for the projectile to reach its maximum height with the formula for final velocity = initial velocity + acceleration (gravity) * The time is 0 = 50 + (-9.81) Once you find the time this time take the total time (7s) and subtract the time you found and then use this time in the formula you just used. It should look like this final velocity = 0 + 9.81 * time is your final velocity component y.

Two Dimensional Projectile Motion, Part 1

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