Preston Meadow's Height Enhancement Blog

Any object that falls or vertical projection in the air had its height above ground h (t), feet ….

t seconds after moving modeled by the quadratic funtion h (t) =- 16t ^ 2 + Vot + Ho, where V is the original initial velocity of the object, in feet per second and H is the initial original height in feet above ground. Height of a rock, a forecast. A rock projecting upward from ground level with an inital velocity of 90 feet per second. Let t represent the amount of time after being released. A. Dar h function that describes the height of the Rock in terms of t. B. If the heighth of the rock that is in 30 feet what is time? C. If the height of the rock is 60 feet, what is time? D. If the height of the rock is at 120ft what is time? E. How High the rock 1.5sec after being released? F. What is the maximum height reached by the rock? After how many seconds? G. After many seconds it reaches the ground? PLEASE PLEASE HELP ME HERE IM Stuck and my current answers are all wrong!

the first equation h (t) =- 16t ^ 2 + Vot + Ho will used to answer a Ho = 0, Vo = 90 h (t) = 90 * T-16 * t ^ 2 and B 30 = 90 * T-16 * t ^ 2 This is a quadratic equation. select the positive root 0 =- 30 +90 * t-16 * t ^ 2 and C 0 =- 60 +90 * t-16 * t ^ 2 again the positive root Thake D. 0 =- 120 +90 * t -16 * t ^ 2 for HE (1.5) = 90 * 1.5 +16 * 1.5 ^ 2 F is a bit more complicated. At the height (maximum height) velocity is zero. The rate follows the equation v (t) = V0-32 * t set equal to zero and connect Vo = 90 t = 90/32 For h G (t) = 0 happens at time zero and the equal-time 0 = 90 * T-16 * t ^ 2 to see how t = 0 is the first (t ) = 0? t = 90/16 is when it returns to earth j

Clayton goes to the Doctor